>I think we might be saying the same thing.
>
>>>1.2 charges on a guy gives 20% chance of 2 charges and 80%
>>>chance of one.
>>>
>>>Therefore if you killed 5 such people you would expect to
>>have
>>>6 charges. However, you might only have 5 or you could
>have
>>>as many as 10 (which would be very unlikely).
>>
>>Why would 1.2 charges give you 80% chance of 1?
>>
>>1.2 would give you 1, and 20% chance of 2.
>>
>
>If you have a 20% chance of getting two charges (which I think
>we are both saying), and the only other possibility is getting
>one charge (which I think we are both saying), then the odds
>of getting one charge must be 80% (100% - 20%).
>
>20% prob of 2 charges, coupled with
>80% prob of 1 charge
>===========================
>100% prob of either 1 or two charges
>
>>Thus the drunk spake, and then was sworded!
>

Mmm...Probability and Statistics...I hated that class.